Declare an array of arrays in Objective-C

Question

How do I declare an array of arrays in Objective-C?

If you're very new to programming, asking questions on Stack Overflow is not the place you need to be. You should find a good book or a series of online tutorials. Have a look at [Good resources for learning ObjC](http://stackoverflow.com/q/1374660). The Big Nerd Ranch books are excellent, and lots of people like the Stanford iOS course on iTunes U. Good luck! — jscs, Feb 24 '14 at 03:28

score 3 · Answer 1 · answered Feb 24 '14 at 03:23

3

For example

NSArray *arr = @[ @[ @'0', @'1', @'2'], 
                  @[ @'0', @'1', @'2']];

answered Feb 24 '14 at 03:23

lighter

2,808
3
40
59

score 2 · Answer 2 · answered Feb 24 '14 at 03:22

2

NSArray *arrayOfArrays = [NSArray arrayWithObjects:
              [NSArray arrayWithObjects:@"Hello!", @"My", @"name", @"is", nil],
              [NSArray arrayWithObjects:@"1", @"2", @"3", @"4", nil], nil];

answered Feb 24 '14 at 03:22

waterproofpiano

73
10

score 2 · Answer 3 · answered Feb 24 '14 at 03:27

Assume you have the objects obj1,obj2,...,obj9

Then this would create an array containing three members:

NSArray *array = @[obj1,obj2,obj3];

And this would create an array of arrays, each containing three members:

NSArray *array = @[ @[obj1,obj2,obj3], @[obj4,obj5,obj6], @[obj7,obj8,obj9] ];

Declare an array of arrays in Objective-C

3 Answers3