Send a blob with ajax, don't work in my case

Asked Feb 24 '14 at 16:37

Active Feb 24 '14 at 16:37

Viewed 195 times

So, i have an image on my page with this for src attribut :

src="blob:47d2cdd6-0ff0-401f-a195-a671d0db9b05"

I need to send this blob to php with ajax, for save this blob (a gif in my case) on my server.

This is my ajax :

var data = new FormData();
data.append('file', $('myImage').attr('src'));

    $.ajax({
        type:"POST",
        url: "/webcam/",
        data: data,
        contentType: false,
        processData: false,
        success: function () {
            parent.$.fancybox.close();
        },
        error: function() {
      alert("not so boa!");
    }
    });

But, when i am on my php script, i don't know how to use this blob... When i try readimageblob() from imagick for example, i have an error.

Am i in the good way ?

asked Feb 24 '14 at 16:37

Clément Andraud

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Why not just send it as a multipart form, as though doing a file upload? – James Black Feb 24 '14 at 16:39
To save that blob as an image on server side, you would do it as a normal upload in php, with : **$_FILES['file']['tmp_name']** – tcj Feb 24 '14 at 16:42
on my ph script, $_FILES['file']['tmp_name'] is null – Clément Andraud Feb 24 '14 at 16:44
Look at the html in this answer: http://stackoverflow.com/a/5587986/67566 – James Black Feb 24 '14 at 16:44
Something like : $('myInputFile').val($('myImage').src) ? And after a submit of this form ? – Clément Andraud Feb 24 '14 at 16:46
What about **$_FILES['file']['tmp_name'][0]** ? – tcj Feb 24 '14 at 16:49
Okay, try to change the variable on data.append like this : **data.append($('input[name=image]').val());** – tcj Feb 24 '14 at 17:04
my blob value is not in an input, it's an image – Clément Andraud Feb 24 '14 at 17:05
You should do it with an input, it works fine for me. – tcj Feb 24 '14 at 17:07
Yeah, but can i change with javascript the value of an input file ? – Clément Andraud Feb 24 '14 at 17:08
No, but why would want to change it ? – tcj Feb 24 '14 at 17:09
Because the blob data is created from a webcam, not from an input.... – Clément Andraud Feb 24 '14 at 17:10
Hmmm, then I can't help you more, sorry, never tried with a webcam. – tcj Feb 24 '14 at 17:13
Then you should look at this, on how to upload from the webcam to php: http://stackoverflow.com/questions/21152926/javascript-webcam-capture-and-upload-to-server-with-php – James Black Feb 24 '14 at 17:32

Send a blob with ajax, don't work in my case

0 Answers0