Is there be a new string object created for S.O.P?

Question

If there are two strings string1 and string2 contained in string pool referenced to String literals, will System.out.println(string1 + string2) generate additional string object in String pool as string3=string1+string2;? If not, why?

Like to add for more clarity how many objects are allocated in pool in such case?

Possible duplicate of [this question](http://stackoverflow.com/questions/11989261/does-concatenating-strings-in-java-always-lead-to-new-strings-being-created-in-m) — Raul Rene, Feb 28 '14 at 12:42

score 2 · Answer 1 · answered Feb 28 '14 at 12:43

2

The expression

"string1" + "string2"

will result in a string constant

"string1string2"

created at compile time and added to the enclosing class's constant pool.

The expression

string1 + string2

where string1 and string2 are arbitrary String-typed variables will compile into executable code which concatenates two strings. The result is not committed to the pool.

answered Feb 28 '14 at 12:43

Marko Topolnik

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and what about System.out.print(string1+"string3"+string2) ? – Prashant Feb 28 '14 at 12:50
The entire expression must be a compile-time constant. The one literal between two variables won't make a difference. – Marko Topolnik Feb 28 '14 at 15:46

Is there be a new string object created for S.O.P?

1 Answers1