Implement my own Java exception

Question

I have to implement my own exception (a GameException) which is thrown by the alpha beta algorithm in a nullsumm game. Is this correct?

import java.lang.Exception;

 public class GameException extends Exception { 

     public static final long serialVersionUID = 3654258946527845L;

     public static final String NoValidMoves = "There are noe valid moves!";


    GameException(String Message) {
        super(Message);
    }
    GameException() {

    }

}

I think your code is correct. In addtion to, you may add some custom methods for your exception class. For exaple; you throw an error code and your method matches the error code explanation and return it for exception message. Good luck ! — Tugrul, Mar 08 '14 at 08:13

Paul Draper · Answer 1 · 2014-03-08T20:50:41.963

3

It's correct.

FYI

You don't need to import java.lang.Exception. The java.lang part means that it is there by default.
By convention, variables in Java are lowerCamelCase.
You don't need to make serialVersionUID public. Any access modifier will work with Serializable, so usually private is chosen.
You misspelled "no".

edited Mar 08 '14 at 20:50

answered Mar 08 '14 at 08:11

Paul Draper

78,542
46
206
285

it **is** calling the no-arg constructor : http://stackoverflow.com/questions/2054022/unnecessary-to-put-super-in-constructor – Svetlin Zarev Mar 08 '14 at 17:27

Implement my own Java exception

1 Answers1