What is the way to separate range and pass the array to the function?

Question

I have array of attachmentList and

if I do

len(attachmentList)

the result is 199930; and I would like to send 999 elements each time to api_request(attachment) function

so pseudo code will be like this

count=0
for (i=0,i<len(attachmentList),i++)
     count++
     if count=999:
       api_request(attachmentList[i-999:i])
       count=0

What is the way to write for loop or there is another solution for that.

You want to "paginate" the list. See answer: http://stackoverflow.com/questions/3950079/paging-python-lists-in-slices-of-4-items — cwa76, Mar 12 '14 at 01:04

score 1 · Answer 1 · answered Mar 12 '14 at 01:11

Use the grouper recipe:

def grouper(iterable, n, fillvalue=None):
    "Collect data into fixed-length chunks or blocks"
    # grouper('ABCDEFG', 3, 'x') --> ABC DEF Gxx
    args = [iter(iterable)] * n
    return izip_longest(fillvalue=fillvalue, *args)

And then:

for chunk in grouper(attachmentList, 1000):
    api_request(chunk)

score 1 · Answer 2 · answered Mar 12 '14 at 01:12

1

You can loop in chunks of 999:

for i in range(0, len(attachmentList), 999):
    api_request(attachmentList[i:i+999])

answered Mar 12 '14 at 01:12

sashkello

17,306
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81
109

score 0 · Answer 3 · answered Mar 12 '14 at 01:06

0

You can use range(...) function as:

previous = 0
for i in range(999,len(attachmentList),999):
    api_request(attachmentList[previous:i]
    previous = i

answered Mar 12 '14 at 01:06

Ruben Bermudez

2,293
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22

What is the way to separate range and pass the array to the function?

3 Answers3