c++ constant reference return declaration of operator = as non function

Question

Please tell what I am doing wrong in this code below, compilor is giving me following error 1. declaration of operator = as non function 2. expected primary expression before const I am not able to identify my mistake

and so on plz help me

#include <iostream>
using namespace std;


class myClass{

    int a;
    int b;

    public:

        myClass();
        myClass(int x, int y);
        const myClass& operator=(const myClass &);  
        void display();     

};


myClass::myClass(){

    a=0;
    b=0;
}
myClass::myClass(int x, int y){
    this->a=x;
    this->b=y;
}

const myClass& myClass::operator=(const class & rightobj){

    if(this!=&rightobj){

        this->a=rightobj.a;
        this->b=rightobj.b;

    }

    return *this;

}

void myClass::display(){

    cout<<a<<endl;
    cout<<b<<endl;
}

int main(){

myClass class1(2,3);
myClass class2;

class2=class1;

class2.display();



return 0;
}

score 4 · Accepted Answer · answered Mar 12 '14 at 19:11

4

Here you have a typo:

const myClass& myClass::operator=(const class & rightobj)
                                       //^^Should be myClass

answered Mar 12 '14 at 19:11

taocp

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ohh thanks i forgot that – user3215228 Mar 12 '14 at 19:11
@user3215228 you're welcome. BTW, `using namespace std` is considered bad practice. You may find a lot of posts here about why if interested. – taocp Mar 12 '14 at 19:12
it's bad practice in a header, it doesn't matter in a .cpp source file – Jonathan Wakely Mar 12 '14 at 19:14
why it is a bad practise?? – user3215228 Mar 12 '14 at 19:14
http://stackoverflow.com/q/5849457/981959 – Jonathan Wakely Mar 12 '14 at 19:17
@user3215228 As it's compiler-only thing, it doesn't really matter unless you work on large team projects. – Saraph Mar 12 '14 at 19:17
@Saraph It **always** matters. – Captain Obvlious Mar 12 '14 at 19:19
@CaptainObvlious Ummmmmm.... **nope**. – Saraph Mar 12 '14 at 19:22

c++ constant reference return declaration of operator = as non function

1 Answers1