Random Average Java

Question

I'm trying to get a program that can generate some random numbers and then find the average of those random numbers, all within set parameters.

Here's what I have so far:

import java.util.*;

public class RandomAverage {

    public static void main(String[] args) 
    {
        Scanner scanner = new Scanner(System.in);
        Random random = new Random();

        System.out.print("Enter n: ");
        int n = Integer.parseInt(scanner.nextLine());

        double sum =

And I know I need to end the program like this:

System.out.print("Computer generated " + n + " random numbers in range between 1 – 100 and the average " + __ + " is: ");
    }
}

you should check out http://stackoverflow.com/questions/363681/generating-random-numbers-in-a-range-with-java , then just add them up and divide by total numbers — mig, Mar 16 '14 at 01:35
Related: http://stackoverflow.com/questions/11441092/java-averaging-a-list-of-numbers?rq=1 — Jason C, Mar 16 '14 at 01:39
Stupid question: Do you know how to take an average? (I mean, on paper, not in a computer program.) — Hot Licks, Mar 16 '14 at 02:24

score 1 · Answer 1 · answered Mar 16 '14 at 01:38

1

If you want to use random integers:

double sum = 0;
for (int i=0; i<n; i++) {
   sum += random.nextInt();
}
double average = sum/n;

Otherwise check out the Javadoc on Random for other means of generating random numbers i.e. within a range etc.

answered Mar 16 '14 at 01:38

xlm

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Random Average Java

1 Answers1