Initialize array variable in structure

Question

I ended up doing like this,

struct init
{
    CHAR Name[65];
};

void main()
{
    init i;

    char* _Name = "Name";

    int _int = 0;

    while (_Name[_int] != NULL)
    {
        i.Name[_int] = _Name[_int];
        _int++;
    }
}

Answer 1

Give your structure a constructor:

struct init
{
  char Name[65];
  init( const char * s ) {
     strcpy( Name, s );
  }
};

Now you can say:

init it( "fred" );

Even without a constructor, you can initialise it:

init it = { "fred" };

Answer 2

In C++, a struct can have a constructor, just like a class. Move the initialization code to the constructor. Also consider using a std::string instead of the char array.

struct init
{
    std::string name;

    init (const std::string &n) : name (n)
    {
    }
};

Answer 3

You could also use strcpy() to copy your string data into the char array.

strcpy(i.Name, "Name");