Java: Parse String with starts with 0 sometimes

Question

I am trying to parse a String to Long which sometimes starts with 0. I want that the result maintains the "0" at the beginning of the Long (e.g. 0247484 instead of 247484).

I have tried this Long.parseLong(city.getId()) but it deletes the first "0".

Thank you

What problem are you trying to solve, and how will this help you solve it? — Elliott Frisch, Mar 18 '14 at 15:08
That's a nonsense. Long represents a number. You cannot store any redundant character there. If you did, how would you implement equals() for example? — NeplatnyUdaj, Mar 18 '14 at 15:14

score 5 · Answer 1 · answered Mar 18 '14 at 15:05

What you are asking for is not possible. In mathematical terms the leading 0 is absolutely meaningless so there is no way to represent it in a long.

What you probably want to do is control the rendering of the Long when you later print it out. There are all sorts of ways to control the formatting of a number, this may help: http://docs.oracle.com/javase/7/docs/api/java/text/NumberFormat.html

score 3 · Answer 2 · answered Mar 18 '14 at 15:05

You should use the DecimalFormat class: http://docs.oracle.com/javase/7/docs/api/java/text/DecimalFormat.html

String number = "0247484";

long parsed = Long.parseLong(number);
System.out.println("Unformatted: " + parsed);

DecimalFormat df = new DecimalFormat("0000000");
String formatted = df.format(parsed);

System.out.println("Formatted: " + formatted);

score 1 · Answer 3 · answered Mar 18 '14 at 15:12

1

Well, if you really need, you can do sth like that:

for example : 08530(string) to long ==> 8530 when you need to convert another time String, you can do :

String.format("%05d", number);

but you need to define a pattern. I hope it helps.

answered Mar 18 '14 at 15:12

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Java: Parse String with starts with 0 sometimes

3 Answers3