converting integer into char explictly

Question

I am trying to convert integer into character. I know how to convert character to integer like this int(a) where a is a character. But when I am trying to convert integer to character, it is giving me a symbolic value. Please help me out.

I am doing something like below. Thanks in advance.

int a=0;
char str1[20];
for(int i=0;i<size;i++)
   //somecalculation that sets value in a everytime and stores in str1 
   str1[i]=char(a)-'A'

Well I am running for loop and setting values in str1. This is just little of my code.

well i am runnig loop where i am calculating something and setting that one digit integer in character array everytime with new digit — user3215228, Mar 18 '14 at 20:11
Can you give an example of input/output that you're looking for? Should f(5) = '5', or something else? — Graphics Noob, Mar 18 '14 at 20:12
You know that the value of 'A' is 65 and that that substraction is resulting in a negative value right? — imreal, Mar 18 '14 at 20:13
Here you can find previous discussions: http://stackoverflow.com/questions/10847237/how-to-convert-from-int-to-char — pari, Mar 18 '14 at 20:32

score 1 · Accepted Answer · answered Mar 18 '14 at 20:14

1

You could use str1[i] = static_cast<char>(a + '0');. This will convert a = 0 to '0', a = 1 to '1' etc. Consider the behaviour as undefined outside the range 0, ..., 9.

answered Mar 18 '14 at 20:14

Bathsheba

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I was actually not taking into account 0 to 9 thanks it worked – user3215228 Mar 18 '14 at 21:11

score 0 · Answer 2 · answered Mar 18 '14 at 20:24

just use sprintf:

for(int i=0;i<size;i++)
//somecalculation that sets value in a everytime and stores in str1 
    sprintf(str1 + i, "%i", a);

since you noted that a is each time only a one digit integer, this should work, but this is not very error prone... normally you should check on how much digits were written:

for(int i=0;i<size;i++)
//somecalculation that sets value in a everytime and stores in str1 
    if (sprintf(str1 + i, "%i", a) != 1)
        printf("expected to print only one character!\n");

converting integer into char explictly

2 Answers2