Initialization of float can be done as follows,
float a = 0.0
float a = 0.f
float a = float(0)
Is there any pros and cons to use any of these?
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possible duplicate of [What is the significance of 0.0f when initializing (in C)?](http://stackoverflow.com/questions/5199338/what-is-the-significance-of-0-0f-when-initializing-in-c) – user1810087 Mar 22 '14 at 07:52
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It doesn't matter at all. You could also say float a = 0; and again it would be the same thing. Or float a = float();. I think the most conventional would be 0, 0.0, or 0f; the rest are just redundant.
John Zwinck
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I'll leave it to the OP to say what they mean, but if they mean other constant values too, everything I said still applies except the bit about `float()`. – John Zwinck Mar 22 '14 at 06:55
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The first initializes from a double literal, whereas the second is from a float literal. The bits in the two zeros may not be the same.
The third is c++ constructor-like syntax that actually just does direct initialization, in this case from an integer literal.
rubenvb
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The bits in a float initialized from a double 0 might differ from one directly from a float 0? How? IEEE 754 has only two ways to represent zero as far as I know, and one is -0 which neither of the above will give you. – John Zwinck Mar 22 '14 at 06:54