Socket-timeout: timed out python requests

Question

Using the requests python lib, I make a GET request, and handle Timeout exceptions (as well as other exceptions I don't show here) like

import requests
timeout1=20
timeout2=40

try:
    #first attempt
    resp = requests.get(base_url+resource, params=payload, headers=headers,
    timeout=timeout1)
except requests.exceptions.Timeout:
    #timed out, retry once
    try:
       resp = requests.get(base_url+resource, params=payload, headers=headers,
       timeout=timeout2)
       return resp.json()
    except requests.exceptions.RequestException as e:
       #Still failed; return error code
       return -1

This works fine most of the time, however sometimes my program just completely exits with the error socket.timeout: timed out, instead of throwing the requests.exceptions.Timeout and this being caught and dealt with.

Why is the requests lib behaving like this? How should I handle this?

Here is the Answer:try: data = sock.recv(256) except socket.timeout: data="NO RESPONSE" — user2801184, Sep 08 '14 at 19:17

score 2 · Answer 1 · edited Feb 19 '16 at 08:29

2

Answer:

try:
    data = sock.recv(256)
except socket.timeout:
    data="NO RESPONSE"

It won't exit!

edited Feb 19 '16 at 08:29

BugShotGG

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answered Sep 08 '14 at 19:18

user2801184

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score 2 · Answer 2 · edited May 23 '17 at 12:07

2

I think this is an issue of the urllib3 that requests uses:

https://github.com/kennethreitz/requests/issues/1236

You'll have to catch that socket.timeout error. (based on jb's comment at Correct way to try/except using Python requests module?)

edited May 23 '17 at 12:07

Community

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answered Feb 19 '16 at 07:59

Botond

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Socket-timeout: timed out python requests

2 Answers2