JSP page:
<input type="file" name="scan_file" accept="application/pdf" id="scan_file" />
Pass file to java class:
$.ajax({
type: "POST",
url: "bank_deposit1",
data: {
scan_file:$("#scan_file").val()
},
success: function(response)
{
alert("done");
},
error: function(e)
{
alert("fail");
}});
File cannot pass into java class.. Why?
try this:
HTML form:
<form id="myForm" action="uploadFileData" method="post" enctype="multipart/form-data">
Enter Your Name:
<input type="text" name="yourname" id="yourname" /><br/>
Select Your Photoes:
<input type="file" name="file" id="file" />
<input type="submit" value="save profile" />
</form>
<div id="response"></div>
and in js do like:
$('form#myForm').submit(function(event){
//disable the default form submission
event.preventDefault();
//grab all form data
var formData = new FormData($(this)[0]);
$.ajax({
url: $(this).attr('action'),
type: "POST",
cache: false,
processData: false,
contentType: false,
data: formData,
success: function (res) {
$("#response").text(res);
},
error: function(jqXHR, textStatus, errorThrown) {
alert(textStatus+' : '+ errorThrown);
}
});
});
Then in servlet save file like:
@WebServlet("/uploadFileData")
@MultipartConfig //in order to let it recognize and support multipart/form-data requests and thus get getPart() to work
public class UploadFileData extends HttpServlet {
private static final long serialVersionUID = 1L;
private String UPLOAD_DIRECTORY;
/**
* @see HttpServlet#doPost(HttpServletRequest request, HttpServletResponse response)
*/
protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
UPLOAD_DIRECTORY = "E:\\";//request.getSession().getServletContext().getRealPath("/upload");
// Set response content type
response.setContentType("text/html");
String yourname = request.getParameter("yourname");
System.out.println(yourname);
Part filePart = request.getPart("file");
String fileName = getFileName(filePart);
System.out.println("fileName:"+fileName);
InputStream fileContent = filePart.getInputStream();
System.out.println("upload dir: "+UPLOAD_DIRECTORY);
File file = new File(UPLOAD_DIRECTORY+fileName);
try{
FileOutputStream fOutputStream = new FileOutputStream(file);
try{
byte[] bytes = new byte[8 * 1024];
int bytesRead;
while((bytesRead = fileContent.read(bytes)) != -1){
fOutputStream.write(bytes, 0, bytesRead);
}
System.out.println("file uploaded successfully..");
response.getWriter().println("file uploaded successfully..");
}finally{
fOutputStream.close();
}
}finally{
fileContent.close();
}
}
/**
* Utility method to extract file name from content-disposition.
* @param filePart
* @return file name
*/
private String getFileName(Part filePart) {
for(String cd: filePart.getHeader("content-disposition").split(";")){
if(cd.trim().startsWith("filename")){
String fileName = cd.substring(cd.indexOf('=')+1).trim().replace("\"", "");
return fileName.substring(fileName.lastIndexOf('/') + 1).substring(fileName.lastIndexOf('\\') + 1); // MSIE fix.
}
}
return null;
}
}
