Accessing res/raw folder in Android

Question

I am trying to create an application in Android. I want to access a file placed in res/raw folder, how can i specify its path while accessing it through File() constructor? And how can I display the file's content using textview?

You cannot access it with the File() constructor as it is not actually a file, but an android-unique construct. Please see the documentation at http://developer.android.com/guide/topics/resources/accessing-resources.html — Chris Stratton, Apr 03 '14 at 17:54

score 0 · Accepted Answer · answered Apr 03 '14 at 17:55

Use InputStream to read file content.

getResources().getIdentifier("raw/FILENAME_WITHOUT_EXTENSION",
                             "raw", getPackageName());

To get it as a InputStream

InputStream ins = getResources().openRawResource(
            getResources().getIdentifier("raw/FILENAME_WITHOUT_EXTENSION",
            "raw", getPackageName()));

OR

InputStream inputStream = getResources().openRawResource(R.raw.yourresource);

refer http://developer.android.com/guide/topics/resources/providing-resources.html for Providing Resources.

Yeah! I got it worked by using InputStream inputStream = getResources().openRawResource(R.raw.yourresource); Thank you:) — user3494875, Apr 04 '14 at 14:47

score 0 · Answer 2 · edited May 23 '17 at 11:49

0

looks like something like this

InputStream raw = context.getAssets().open("filename.ext");

Reader is = new BufferedReader(new InputStreamReader(raw, "UTF8"));

taken from here: Android how to get access to raw resources that i put in res folder?

Another way I thought you could do it is to use getResources(), and access it via R.raw.fileName

edited May 23 '17 at 11:49

Community

1
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answered Apr 03 '14 at 18:16

reidisaki

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Yeah! I got it worked by using InputStream inputStream = getResources().openRawResource(R.raw.yourresource); Thank you:) – user3494875 Apr 04 '14 at 14:47

Accessing res/raw folder in Android

2 Answers2