Show integer as binary sequence (java)

Question

Say I have an integer number: 11728322732 how can i convert it to a string according to its byte representation, i.e 11100011000000001100000111110001 (32 bits \ 4 bytes \ integer)

Thanks

xav · Answer 1 · 2014-04-03T22:40:47.107

0

Here it is:

Long.toBinaryString(11728322732L);

Actually, 11728322732 is not an Integer but a Long (because it is greater than Integer.MAX_VALUE). So if you really want to convert this long to a 32-bits int (can't figure why actually), you could do:

Integer.toBinaryString((int)11728322732L);

edited Apr 03 '14 at 22:40

answered Apr 03 '14 at 22:32

xav

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Good answer, but that number is bigger than `Integer.MAX_VALUE` ;) – aliteralmind Apr 03 '14 at 22:34
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@aliteralmind good one. Fixed it! – xav Apr 03 '14 at 22:35
I use integers so Integer.toBinaryString(...) works just fine, thanks – TomM12 Apr 03 '14 at 22:41
Does anyone knows how can I convert a binary representation back to int ? for instance 11000000 to 192 ? – TomM12 Apr 03 '14 at 22:42
`Integer.parseInt("11000000", 2);` (that means _"convert it from base 2"_) – xav Apr 03 '14 at 22:43

Show integer as binary sequence (java)

1 Answers1