my code
$query = "SELECT `url` FROM `$drop` WHERE `vidname`= '$tier_two'";
$dave= mysql_query($query) or die(mysql_error());
    echo "<p>";
print $query;
im trying to the url feild to echo but im coming up with blanks
my code
$query = "SELECT `url` FROM `$drop` WHERE `vidname`= '$tier_two'";
$dave= mysql_query($query) or die(mysql_error());
    echo "<p>";
print $query;
im trying to the url feild to echo but im coming up with blanks
 
    
    you can do something like:
$result = mysqli_query($query);
$row = mysqli_fetch_array($result);
extract($row);
echo $url;
note: printing $query is printing your sql command.., for printing your query result, you can use my suggestion or @Companjo 's suggestion (ah, his post was deleted).. and (as @Phil's comment) the reason to use mysqli_* is because mysql_* is deprecated..
reference:
http://php.net/manual/en/mysqli-result.fetch-array.php
you might want to see the connection creation using mysqli here (if you decide to use mysqli_*):
http://php.net/manual/en/mysqli.quickstart.connections.php
addition: mysql_ and mysqli_ don't differ much.. you'll realize it as you trying it..
 
    
    You can try this:
$query = mysql_query("SELECT url FROM '$drop' WHERE vidname= '$tier_two'");  
while($row = mysql_fetch_array($query)){    
  $url = $row["url"];   
  echo $url;
}
 
    
    