Convert StreamResult to string or xml

Question

Using spring ws to get the StreamResult as below

StreamSource source = new StreamSource(new StringReader(MESSAGE));
StreamResult result = new StreamResult(System.out);
webServiceTemplate.sendSourceAndReceiveToResult("http://someUri", 
                source, new SoapActionCallback("someCallBack"), result); 
return result;

I get the result, But I want to extract it to some sort of xml or even as a string (Just want to see the contents in order to generate the response).

How can I do this?

http://stackoverflow.com/questions/22939440/how-to-get-soap-response-from-webservicetemplate/22939680#22939680 might help — VirtualTroll, Apr 22 '14 at 12:56

score 58 · Accepted Answer · edited Feb 17 '16 at 12:00

Try this one:

try {
    StreamSource source = new StreamSource(new StringReader("<xml>blabla</xml>"));
    StringWriter writer = new StringWriter();
    StreamResult result = new StreamResult(writer);
    TransformerFactory tFactory = TransformerFactory.newInstance();
    Transformer transformer = tFactory.newTransformer();
    transformer.transform(source,result);
    String strResult = writer.toString();
} catch (Exception e) {
    e.printStackTrace();
}

score 5 · Answer 2 · answered Apr 22 '14 at 12:49

5

You can get the reader of your StreamSource by using getReader(). You should then be able to use read(char[] cbuf) to write the contents of the stream to a character array which can easily be converted into a string and printed to the console if you wish.

answered Apr 22 '14 at 12:49

Lex Webb

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I am interested in only StreamResult – user1609085 Apr 22 '14 at 12:53
StreamResult is a writer class, you cannot get any data from a writer class as it passes on all data passed to it. And does not store the data. See the definition here: http://docs.oracle.com/javase/7/docs/api/javax/xml/transform/stream/StreamResult.html – Lex Webb Apr 22 '14 at 13:00

score 3 · Answer 3 · answered Jul 06 '16 at 05:22

If none of these works, try this

System.out.println(result.getOutputStream().toString());

Assuming you have this kind of structure ,

private static StreamResult printSOAPResponse(SOAPMessage soapResponse) throws Exception {
    TransformerFactory transformerFactory = TransformerFactory.newInstance();
    Transformer transformer = transformerFactory.newTransformer();
    Source sourceContent = soapResponse.getSOAPPart().getContent();
    System.out.print("\nResponse SOAP Message = ");
    StreamResult result = new StreamResult(System.out);
    transformer.transform(sourceContent, result);
    return result;
}

You can try this way , although the same thing, wanted to point it out clearly

System.out.println(printSOAPResponse(soapResponse).getOutputStream().toString());

score 3 · Answer 4 · answered Aug 10 '18 at 14:14

If you use Spring you could also use this way:

    import org.springframework.core.io.Resource;
    import org.apache.commons.io.IOUtils;
    ....    
    @Value("classpath:/files/dummyresponse.xml")
    private Resource dummyResponseFile;
    ....
    public String getDummyResponse() {
        try {
            if (this.dummyResponse == null)
                dummyResponse = IOUtils.toString(dummyResponseFile.getInputStream(),StandardCharsets.UTF_8);
        }  catch (IOException e) {
            logger.error("Fehler in Test-Service: {}, {}, {}", e.getMessage(), e.getCause(), e.getStackTrace());
            throw new RuntimeException(e);
        }
        return dummyResponse;
    }

Convert StreamResult to string or xml

4 Answers4

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