How to parse this json string?

Question

i want to parse this json.i have difficulty when i try to parse the following json.suggest me proper way of parsing following json.i edit my code ,noe this is the correct code that i want to parse.

  {
"tag":{
    "tag1":1,
    "tag2": "colour",
    "tag3":"value",
    "tag4":"value",
    "tag5":1,
    "tag6":1,
    "tag7":true,
    "tag8": [
            {
            "t1":"Red",
            "t2":"int",
            "t3":1,
            "t4":true
            },
            {
            "t1":"Green",
            "t2":"int",
            "t3":2,
            "t4":true
            },
            {
            "t1":"Blue",
            "t2":"int",
            "t3":3,
            "t4":true
            }
             ],
    "tag9":null,
    "tag10":1
},
"tag":{
    "tag1":2,
    "tag2": "value",
    "tag3":"value",
    "tag4":"value",
    "tag5":1,
    "tag6":1,
    "tag7":true,
    "tag8": [
            {
            "t1":"value",
            "t2":"value",
            "t3":true,
            "t4":true,

            },
            {
            "t1":"value",
            "t2":"value",
            "t3":false,
            "t4":true,

            }
             ],
    "tag9":1,
    "tag10":3
},
"tag":{
    "tag1":5,
    "tag2": "value",
    "tag3":"value",
    "tag4":"value",
    "tag5":1,
    "tag6":1,
    "tag7":false,
    "tag8": null,
    "tag9":null,
    "tag10":null
}

}

i had used this code        
    try {
        JSONObject json= (JSONObject) new JSONTokener(loadJSONFromAsset()).nextValue();
        JSONObject json2 = json.getJSONObject("tag");
        for (int i = 0; i < json.length(); i++) {
            int tag1 = (Integer) json2.get("tag1");
            String tag2 = (String) json2.get("tag2");
            String tag3 = (String) json2.get("tag3");
            String tag4 = (String) json2.get("tag4");
            int tag5 = (Integer) json2.get("tag5");
            int tag6 = (Integer) json2.get("tag6");
            boolean tag7 = json2.getBoolean("tag7");
            if (!json2.isNull("tag8")) {
                JSONArray jArray = json2.getJSONArray("tag8");
                JSONObject json_data = null;
                for (int i1 = 0; i1 < jArray.length(); i1++) {
                    json_data = jArray.getJSONObject(i1);
                    String Label = json_data.getString("t1");
                    String ValueType = json_data.getString("t2");
                    int Value = json_data.getInt("t3");
                    boolean isNextEnabled = json_data.getBoolean("t4");
                }
            }
            int previous = 0;
            if (!json2.isNull("tag9")) {

                 previous= (Integer) json2.get("tag9");
            }
            int next = 0;
            if (!json2.isNull("tag10")) {

                next = (Integer) json2.get("tag10");
            }
        }
    } catch (JSONException e) {
        e.printStackTrace();
    }


public String loadJSONFromAsset() {
    String json = null;
    try {

        InputStream is = getAssets().open("myjson");

        int size = is.available();

        byte[] buffer = new byte[size];

        is.read(buffer);

        is.close();

        json = new String(buffer, "UTF-8");


    } catch (IOException ex) {
        ex.printStackTrace();
        return null;
    }
    return json;

}
}

i get only last record ,how do i get all data .any help will be appreciated thanks...

Are all these dynamic or fixed?-> "tag" and tag1, tag2, t1,t2, "responses" — Pararth, Apr 25 '14 at 12:11
There are redundant `tag` keys, are you sure this is your JSON because even `JsonValidator` also returns the last `tag` key only. — Spring Breaker, Apr 25 '14 at 12:13
You can try this parser https://jsonparser.online/ to verify JSON data online — Devidas M Das, Jun 06 '20 at 15:59

itsben · Answer 1 · 2014-04-25T13:31:34.027

0

The JSONOject has a constructor that accepts a string of JSON data. You can use the constructor to parse the JSON string. If the string is valid JSON data, the constructor will return a JSONObject. If the string is NOT valid JSON, the constructor will throw an error. It's good practice to wrap the constructor inside of a try/catch block.

String json = "{name:\"value\"}";
JSONObject item = null;
try{
  item = new JSONObject(json);
}catch(Exception exc){
  Log.d(TAG, exc.toString());
}
if(item != null){
  Log.d(TAG, String.format("name:%s", item.getString("name")));
}

edited Apr 25 '14 at 13:31

answered Apr 25 '14 at 12:15

itsben

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Consider adding explanation. Plain code rarely helps in the long run. – Joffrey Apr 25 '14 at 12:54
Good point. I will update the answer. – itsben Apr 25 '14 at 13:21

score 0 · Answer 2 · answered Apr 25 '14 at 12:42

You can try to parse your string @ http://json.parser.online.fr/ it works nice for me.

From static review of the JSON string it seems you have "tag" element 3 times in your input and due to that parser might get confused. Try to remove duplicate entries and then try.

How to parse this json string?

2 Answers2