On jquery.popover openEvent call function in jquery?

Question

I want to call function on openEvent but it doesn't work. I'm using this jquery plugin.

My code is mentioned below:

$("#verified_icon").popover({
                title: "",
                content: "You have a fanbase of over 1000 Amount of fans they have.",
                hideOnHTMLClick: false,
                openEvent: 'localhost/project/common_ctrl/update_popup_status',
                trigger: 'hover',
            });
            $("#verified_icon").popover('show');

anybody help me......... thanks in advance

I use jquery.popover plugin.... https://github.com/kematzy/jquery-popover — tusharchavda007, Apr 28 '14 at 07:29
This looks odd to me : `openEvent:'localhost/project/common_ctrl/update_popup_status'`. What are you trying to achieve here? — frhd, Apr 28 '14 at 07:34
Your callback function obviously should follow the [rules for valid JavaScript variable names](http://stackoverflow.com/questions/1661197/valid-characters-for-javascript-variable-names) — frhd, Apr 28 '14 at 07:44
i will update the status in database that pop up pops there only once time....... — tusharchavda007, Apr 28 '14 at 08:22
`openEvent:` will call a function. Where is that function in your javascript code? — frhd, Apr 28 '14 at 08:34
According to the documentation provided in your link, thats how it works. However, you can implement your logic in a callback function provided in `openEvent`. HTH. — frhd, Apr 28 '14 at 08:47

score 1 · Accepted Answer · answered Apr 28 '14 at 08:55

You seem to be trying to specify a http route in this parameter, which probably will not work.

According to the docs for the jquery plugin kematzy/jquery-popover, you should specify a callback function in the openEvent parameter. You can implement your desired logic within this function.

On jquery.popover openEvent call function in jquery?

1 Answers1