C++ How to output int as 32-bit binary?

Question

I want to output an int in 32-bit binary format. Is looping and shifting my only option?

32-bit binary format. What I meant is in the answer output. Is it not clear? Shall I edit my question? — Varaquilex, Apr 30 '14 at 09:11
Duplicate http://stackoverflow.com/questions/7349689/c-how-to-print-using-cout-the-way-a-number-is-stored-in-memory — Moberg, Apr 30 '14 at 09:14
@Varaquilex Well, it wasn't clear to me that you meant a text format. I guess I'm to used to hearing people use the word binary to mean not text. — James Kanze, Apr 30 '14 at 09:43

score 6 · Accepted Answer · answered Apr 30 '14 at 09:06

Looping is a way. You can also use bitset library.

#include <iostream>
#include <bitset>

int main(int argc, char** argv) {

    int i = -5, j = 5;
    unsigned k = 4000000000; // 4 billion
    std::cout << std::bitset<32>(i) << "\t" << std::bitset<32>(j) << std::endl;
    std::cout << std::bitset<32>(k) << std::endl;

    return 0;
}

And the output will be:

11111111111111111111111111111011       00000000000000000000000000000101
11101110011010110010100000000000

C++ How to output int as 32-bit binary?

1 Answers1