Display string from Nsarray only if it contains

Question

I am using the following query to check if the strings within a NSArray contain a certain word.

I am struggling to then break it down to display only the string that has the rangeOfString word.

As you can see it currently displays all the results if the NSArray contains the word. How would I single it down further to display only the specific string that contains the "BOLDME" ?

// change this line only for the concatenation
        NSString * resultConditions = [legislationArray componentsJoinedByString:@"\n"];

        NSString *word = @"BOLDME";
        //if string contains
        if ([resultConditions rangeOfString:word].location != NSNotFound) {

            cell.dynamicTextView.text = resultConditions;

        }

why not just to iterate over NSArray and check each string if it contains that string? for(NSString *value in array) if([value rangeOfString:word] != NSNotFound) { /* we have found that string*/ } — AndrewShmig, May 03 '14 at 19:33
@MidhunMP so For each string in array do the query? how would I then add them all to the textView? — memyselfandmyiphone, May 03 '14 at 19:35
@memyselfandmyiphone: I'm not clear about your requirement. I think you need to only display all strings which contains that particular word. Right ? — Midhun MP, May 03 '14 at 19:46
hi @MidhunMP. To be honest I don't think my question was clear at all reading over it (Im very tired). Ideally I am looking at how to make that particular string bold as well as display the rest of the strings — memyselfandmyiphone, May 03 '14 at 19:58
You can use NSAttributedString class and NSAttributedText property for that — Midhun MP, May 03 '14 at 19:59
@MidhunMP instead of what is suggested below or within the if loop? — memyselfandmyiphone, May 03 '14 at 20:01
@memyselfandmyiphone: That answer is correct, for making bold you need to use the above things inside the if block of that code. Also check [1](http://stackoverflow.com/questions/3586871/bold-non-bold-text-in-a-single-uilabel) and [2](http://stackoverflow.com/questions/6013705/any-way-to-bold-part-of-a-nsstring) — Midhun MP, May 03 '14 at 20:04

score 2 · Accepted Answer · answered May 03 '14 at 19:34

Not only will this get you directly to each instance within the array that contains the text you're searching for, but it will also perform significantly better than the code in the question.

for (NSString *testWord in legislationArray) {
    if ([testWord rangeOfString:@"BOLDME"].location != NSNotFound) {
        // testWord contains "BOLDME"
        cell.dynamicTextView.text = 
            [cell.dynamicTextView.text stringByAppendingString:testWord];
    }
}

As written, this will append the found string to whatever text is already in the text view. It may be that you only want one word in the text view. If this is the case, then you should break; as soon as you find the first one.

perfect.I will accept when it lets me. I must be real tired to of overlooked some of this. — memyselfandmyiphone, May 03 '14 at 19:39

score 1 · Answer 2 · edited May 03 '14 at 19:35

1

You can iterate over NSArray and check each string if it contains specific word:

for(NSString *value in array) {
    if([value rangeOfString:word] != NSNotFound) { 
        /* we have found that string*/ 
     }
}

edited May 03 '14 at 19:35

nhgrif

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answered May 03 '14 at 19:35

AndrewShmig

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Display string from Nsarray only if it contains

2 Answers2