XPATH get all nodes between text_1 and text_2

Question

I have HTML like this

<div>
text1
<a>link_1</a>
<a>link_2</a>
text2
<a>link_3</a>
text3
</div>

I want to get all the nodes between text1 and text2. The problem is there is no p or span tag. There are only plain text with content is text1 and text2.

How could I do this with XPATH? Thank you!

har07 · Accepted Answer · 2014-05-05T04:42:39.893

4

How about this way :

/div/*
    [
        preceding-sibling::text()[normalize-space(.) = 'text1'] 
            and 
        following-sibling::text()[normalize-space(.) = 'text2']
    ]

edited May 05 '14 at 04:42

answered May 05 '14 at 03:09

har07

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fixed the answer :) try it out – har07 May 05 '14 at 04:43
1

Awesome! Thank you very much. So we have to remove trailing space :) – neo0 May 05 '14 at 05:41
2

If you want to select text nodes also,, for example if you wanted all between "text1" and "text3", you'd have to replace the `/div/*` part with `/div/node()` – paul trmbrth May 05 '14 at 11:00
Yeah, in my case I only want to get the `href` attribute inside `a` tag. I use //div/a[...] – neo0 May 05 '14 at 14:13

XPATH get all nodes between text_1 and text_2

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