Difference between 08 and 8 in for int variable in java

Question

I have declared a variable int i = 08; I got an error in netbeans that "integer number too large"! Can anyone explain why this happens. I am coding in Java.

for (int i = 08; l <= Integer.parseInt(dd); i++)

To remove the error I then tried int i = 8 which works; Now I do not understand that why int i = 08 do not work?

Googling for "java integer number too large 08" gives many results from which the answer could easily have been derived. Additionally, there are some duplicate questions on SO. So, why got this question upvoted? — Seelenvirtuose, May 08 '14 at 07:08

score 8 · Accepted Answer · answered May 08 '14 at 06:58

8

Literal integer types starting at 0 are interpreted as octal base. Octal base doesn't allow 8, only digits from 0 to 7.

answered May 08 '14 at 06:58

Luiggi Mendoza

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score 2 · Answer 2 · answered May 08 '14 at 06:59

2

If you write '0' as leading it indicate Octal

answered May 08 '14 at 06:59

Sanjay Rabari

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score 1 · Answer 3 · answered May 08 '14 at 06:58

1

Leading 0 suggests 8-based number system, so viable digits there are 0 - 7

answered May 08 '14 at 06:58

endriu_l

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score 1 · Answer 4 · answered May 08 '14 at 06:58

1

The prefix "0" indicates "octal", and 8 is larger than the maximum-sized octal digit.

answered May 08 '14 at 06:58

Michael Aaron Safyan

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score 0 · Answer 5 · answered May 08 '14 at 07:16

The prefix 0 indicates octal(8 base)(digits 0-7).

public class MainClass{

  public static void main(String[] argv){

    int intValue = 034;  // 28 in decimal
    int six = 06; // Equal to decimal 6
    int seven = 07; // Equal to decimal 7
    int eight = 010; // Equal to decimal 8
    int nine = 011; // Equal to decimal 9

    System.out.println("Octal 010 = " + eight);

  }

}

Difference between 08 and 8 in for int variable in java

5 Answers5