I've got a query which I want to convert to use prepared statements, but I can't figure out how!
The code below is working code, but not safe because it's not using prepared statements. I want the function getUser to return the same result as it does now; can anyone tell me how to convert this?
$results = getUser('myUser@test.com');
foreach($results as $result) {
    echo $result['email'];
}
function getUser($email){
    $con = DBConnect();
    $result = mysqli_query($con,"SELECT * FROM tbl_appl_users WHERE email='".$email."'");
    $resultArray = array(); 
    while($row = mysqli_fetch_array($result)) {
        array_push($resultArray,$row);
    }
    return $resultArray;
    mysqli_close($con);
}
I know how to set up the prepared statement, but don't know how to process it. In the example code the query is requesting a single value but I want to get all values returned. The function as far as I got it is below:
function getUser($email){
    $con = DBConnect();
    $resultArray = array(); 
    if ($stmt = $con->prepare("SELECT * FROM tbl_appl_users WHERE email=?")) {
        $stmt->bind_param("s", $email);
        $stmt->execute();
        //$stmt->bind_result($district); // how to do this for a * result set.
        $stmt->fetch();
        while($row = mysqli_fetch_array($stmt)) {
            array_push($resultArray,$row);
        }
        //printf("%s is in district %s\n", $city, $district);
        $stmt->close();
    }
    return $resultArray;
    mysqli_close($con);
}
 
    