How to grep for specific pattern in a file

Question

I have a bash file that has below line along with other lines.

var BUILD_VERSION       = '2014.17.10_23';

I just want to extract 2014.17.10_23 and this value may change so something like grep for 2014* . However when I do that I get the whole line returned instead of the value 2014.17.10_23.

What would be the best way to achieve this?

Thanks

Your regex effectively looks for `201`; you want something like `grep -oP "^var[ ]*BUILD_VERSION[ ]*=[ ]*'\K[^']*"` — tripleee, May 09 '14 at 04:15
@tripleee You should post that as an answer. It's a great solution and will be a good reference for others. You'll have my up-vote for it. `:)` — jaypal singh, May 09 '14 at 04:50
@Jaypal You will find hundreds, if not thousands, of duplicates for this question. Please nominate to close as a duplicate instead of posting repetitive trivial answers. If you find a better dupicate, please link to it. If you find that the designated duplicate lacks a particular variant of the standard answers, feel free to add it there. — tripleee, May 09 '14 at 06:13

perreal · Accepted Answer · 2014-05-09T04:18:46.270

2

Using awk:

awk -F= '/BUILD_VERSION/{print $2}' input | tr -d "[' ;]"

And with sed:

sed -n "/BUILD_VERSION/s/.*'\([^']*\)'.*/\1/p" input

edited May 09 '14 at 04:18

answered May 09 '14 at 04:12

perreal

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This command works awk -F= '/BUILD_VERSION/{print $2}' input | tr -d "[' ;]" The values in the souce file i am getting from below command unzip -c work/$todeployname/warfile.war app/config/Property.js > /app/deployments/svnbuild.tmp . So instead of writing to a tmp file how can I directly feed that output of unizp - c to this command to get the build number awk -F= '/BUILD_VERSION/{print $2}' input | tr -d "[' ;]" – user1432622 May 14 '14 at 17:41

score 1 · Answer 2 · answered May 09 '14 at 04:10

1

grep 'BUILD_VERSION' <your file> | sed -e 's/var BUILD_VERSION = //g'

Would get you '2014.17.10_23'; tweak the sed expression (or pipe it through a few more) to get rid of quotes.

It would be a 1 liner regex in Perl...

answered May 09 '14 at 04:10

John3136

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This command works awk -F= '/BUILD_VERSION/{print $2}' input | tr -d "[' ;]" The values in the souce file i am getting from below command unzip -c work/$todeployname/warfile.war app/config/Property.js > /app/deployments/svnbuild.tmp . So instead of writing to a tmp file how can I directly feed that output of unizp - c to this command to get the build number awk -F= '/BUILD_VERSION/{print $2}' input | tr -d "[' ;]" – – user1432622 May 14 '14 at 17:51

score 1 · Answer 3 · answered May 09 '14 at 04:17

1

Here is another awk solution:

awk -F' = ' '/BUILD_VERSION/ {gsub(/\x27|;/,""); print $NF}'

answered May 09 '14 at 04:17

jaypal singh

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This command works awk -F= '/BUILD_VERSION/{print $2}' input | tr -d "[' ;]" The values in the souce file i am getting from below command unzip -c work/$todeployname/warfile.war app/config/Property.js > /app/deployments/svnbuild.tmp . So instead of writing to a tmp file how can I directly feed that output of unizp - c to this command to get the build number awk -F= '/BUILD_VERSION/{print $2}' input | tr -d "[' ;]" – – user1432622 May 14 '14 at 17:51
@user1432622 pipe the output `your_command | awk ...` – jaypal singh May 14 '14 at 17:54
Yes but how do I refer the filename from your_command after the pipe in awk command? – user1432622 May 16 '14 at 23:48

score 0 · Answer 4 · answered May 09 '14 at 07:24

0

You can use this awk

awk -F\' '/BUILD_VERSION/ {print $2}' file
2014.17.10_23

answered May 09 '14 at 07:24

Jotne

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This command works awk -F= '/BUILD_VERSION/{print $2}' input | tr -d "[' ;]" The values in the souce file i am getting from below command unzip -c work/$todeployname/warfile.war app/config/Property.js > /app/deployments/svnbuild.tmp . So instead of writing to a tmp file how can I directly feed that output of unizp - c to this command to get the build number awk -F= '/BUILD_VERSION/{print $2}' input | tr -d "[' ;]" – – user1432622 May 14 '14 at 17:52
@user1432622 I am not familiar with how to get data from unzip. But you can remove the `tr` command. `awk -F= '/BUILD_VERSION/ {gsub(/[; \x27]/,"",$2);print $2}' input` The `\x27` creates the single quote `'` – Jotne May 14 '14 at 18:05

How to grep for specific pattern in a file

4 Answers4