Remove the empty string in the result of `split("");`

Question

I want a String[] that shows this:

Value1: [0, 0, 0, 0, 0, 0, 0, 1]

But when I use String[] b1 = sByte.split("");, I get

Value1: [, 0, 0, 0, 0, 0, 0, 0, 1]

That extra position isn't supposed to be there. Is there any way to remove it?

@njzk2 probably a set of bits saved as string, something like `"00000001"` — A4L, May 22 '14 at 16:54
[here is a similar question](http://stackoverflow.com/q/22718096/1113392) — A4L, May 22 '14 at 16:57
Do you really need to do it with do it with regex? Why not just use `sByte.toCharArray()` and get a `char[]` as result, if those are supposed to be bit values, this would be more handy to work with (comparison with 0 and 1 using == operator)... — A4L, May 22 '14 at 17:04

score 0 · Answer 1 · answered May 22 '14 at 17:02

0

You can split it on a location that is both preceded by and followed by any character:

String[] b1 = sByte.split("(?<=[\\s\\S])(?=[\\s\\S])");

answered May 22 '14 at 17:02

1 Answers1