Regarding intern() method in String

Question

String s1=new String("Raam");
String s2=s1.concat("Kumar");
String s3=s2.intern();
String s4="RaamKumar";
System.out.println("s3==s4..."+(s3==s4)); //true

intern() method checks whether particular object exiting in String Constant pool or not . Oterwise it will create that object in String Constant pool. But What is the need of String intern().which scenario it is useful?

Did you read this? http://stackoverflow.com/questions/1091045/is-it-good-practice-to-use-java-lang-string-intern — Alexis C., May 22 '14 at 20:47
What's gonna happen if you don't do the `s2.intern()` doesn't it automatically get interned? — Farhad Alizadeh Noori, May 22 '14 at 20:57
@FarhadAliNoo Interning is only done automatically for string literals present in the source code — awksp, May 22 '14 at 21:02

score 0 · Answer 1 · answered May 22 '14 at 20:49

0

It is almost never useful. As per String class documentation, String literals are always interned. That is, if I say

String a = "A String";
String b = "A String";

, a single object will be put on the heap and both a and b will point to the same reference.

So, I would say this is syntactic sugar that makes any call to intern() unneeded.

answered May 22 '14 at 20:49

Andrei Nicusan

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The question concerned when it was useful not when it wasn't. – biziclop May 22 '14 at 20:53

Regarding intern() method in String

1 Answers1