Using JMenu or JMenuItem, my Exit button does not work

Question

I am using the following code, I tried to implement an Exit button, but it does nothing when it is pressed.

JMenuBar menuBar = new JMenuBar();
setJMenuBar( menuBar );
JMenuItem menuClose = new JMenu( "Exit" );
menuClose.setToolTipText("Exit application");

menuClose.addActionListener( new ActionListener(){
    public void actionPerformed( ActionEvent e ){
        System.exit(0);
    }
});

menuBar.add( menuClose );

Ideas?

You should probably create a `JMenu`, then create a `JMenuItem` and add it to the `JMenu`. — APerson, May 24 '14 at 00:15

score 2 · Answer 1 · answered May 24 '14 at 01:18

You should probably create a JMenu, then create a JMenuItem and add it to the JMenu.

So, your code would look like :

JMenuBar menuBar = new JMenuBar();
setJMenuBar( menuBar );
JMenu menu = new JMenu("Exit");
JMenuItem menuClose = new JMenuItem( "Exit application" );
menuClose.setToolTipText("Exit application");
menu.add(menuClose);
menuBar.add(menu);

score 0 · Answer 2 · edited May 23 '17 at 12:27

0

Try this instead

setVisible(false);
dispose();

as seen here https://stackoverflow.com/a/1235321/2833217

edited May 23 '17 at 12:27

Community

1
1

answered May 24 '14 at 01:00

jrasm91

394
2
10

This assumes that the frame's `defaultCloseOpertation` is set to `EXIT_ON_CLOSE` – MadProgrammer May 24 '14 at 01:02

Using JMenu or JMenuItem, my Exit button does not work

2 Answers2