upload file and save it with original name

Question

I need to have web form for upload files. I want save uploaded file with original name.

I have this PHP code:

<form action="" enctype="multipart/form-data" method="POST">
  <input type="file" name="file" /> <br />
  <input type="submit" value="Upload" />
</form>

<?php
  if ( ($_SERVER['REQUEST_METHOD'] == 'POST') ) {
    $fieldname = $_REQUEST['file'];
    $tmpfile = $_FILES[$fieldname]['tmp_name'];

    $info = pathinfo($tmpfile);
    $filename = 'newfile.' . $info['extension'];

    $uploaddir = 'uploads/';
    $uploadfile = $uploaddir . $filename;

    if(move_uploaded_file($tmpfile, $uploadfile)) {
      echo $uploadfile;
    }

  }
?>

but after user upload file I have tmp_name file on server.

What I need: user upload file photo123.jpg - I want photo123.jpg on server. User upload firefox.exe - I want firefox.exe

check this `http://www.w3schools.com/php/php_file_upload.asp` — Sathya Baman, Jun 10 '14 at 11:21

AkshayP · Answer 1 · 2014-06-10T11:43:12.593

1

try this :

$fieldname = $_FILES['file']['name'];

instead of $fieldname = $_REQUEST['file'];

edited Jun 10 '14 at 11:43

answered Jun 10 '14 at 11:19

AkshayP

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please let me know if it's working for you. – AkshayP Jun 10 '14 at 11:21
I don't see how this helps at all; judging from the code shared, `$fieldname` should rightfully be `"file"` and not the uploaded file name. – Ja͢ck Jun 10 '14 at 11:39

score 1 · Accepted Answer · answered Jun 10 '14 at 11:25

try with $_FILES['file']['name']

if ( ($_SERVER['REQUEST_METHOD'] == 'POST') ) {
    $tmpfile = $_FILES['file']['tmp_name'];
    $filename = $_FILES['file']['name'];
    $uploaddir = 'uploads/';
    $uploadfile = $uploaddir . $filename;
    if(move_uploaded_file($tmpfile, $uploadfile)) {
      echo $uploadfile;
    }
  }

upload file and save it with original name

2 Answers2