Python Raise Error (to display in shell) , then do rest of the code

Question

I have a file called dictionary.txt, it contains one word in English, a space and then the Georgian translation for that word in each line.

My task is to raise an error whenever an English word without a corresponding word is found in the dictionary (e.g. if the English word has no translation).

If I raise a ValueError or something like that it stops the code. Could you provide me with an example(using try if there is no other option).

def extract_word(file_name):
    final = open('out_file.txt' ,'w')
    uWords = open('untranslated_words.txt', 'w+')
    f = open(file_name, 'r')
    word = ''
    m = []
    for line in f:
        for i in line:
            if not('a'<=i<='z' or 'A' <= i <= 'Z' or i=="'"):
                final.write(get_translation(word))
            if word == get_translation(word) and word != '' and not(word in m):
                m.append(word)
                uWords.write(word + '\n')
                final.write(get_translation(i))
                word=''
            else:
                word+=i
    final.close(), uWords.close()

def get_translation(word):
    dictionary = open('dictionary.txt' , 'r')
    dictionary.seek(0,0)
    for line in dictionary:
        for i in range(len(line)):
            if line[i] == ' ' and line[:i] == word.lower():
                return line[i+1:-1]
    dictionary.close()
    return word

extract_word('from.txt')

Please attach your code, Also it's not clear what you are asking. — Kobi K, Jun 12 '14 at 08:18
The question was clear to me :/ - You task is simple - create a dictionary from your translation word list. Each key is the English word, and the value is the translated word. If you lookup a key in a dictionary that doesn't exist, then `KeyError` will be raised and just like any other exception, if you don't catch it the program will terminate automatically. To prevent this from happening, you can use the `get()` method of the dictionary, this will return `None` if a key doesn't exist, and then you can print an appropriate message. — Burhan Khalid, Jun 12 '14 at 10:07

score 0 · Answer 1 · answered Jun 12 '14 at 08:28

0

Raising an error is primarily to allow the program to react or terminate. In your case you should probably just use the Logging API to output a Warning to the Console.

import logging

logging.warning('Failed to find Georgian translation.') # will print a warning to the console.

Will result in the following output:

WARNING:root:Failed to find Georgian translation.

answered Jun 12 '14 at 08:28

Insomniac

446
7
15

Thanks but it has to raise error, warning is not the solution but i'll keep it in mind – temo Jun 12 '14 at 09:44

score 0 · Answer 2 · answered Jun 12 '14 at 08:28

0

You should probably take a look at this

f = open('dictionary.txt')
s = f.readline()
try:
    g = translate(s)
except TranslationError as e:
    print "Could not translate" + s

Assuming that translate(word) raises a TranslationError of course.

answered Jun 12 '14 at 08:28

Ariel Voskov

326
3
7

score 0 · Accepted Answer · answered Jun 12 '14 at 08:32

0

The question is not very clear, but I think you may need this kind of code:

mydict = {}
with open('dictionary.txt') as f:
    for i, line in enumerate(f.readlines()):
         try:
              k, v = line.split() 
         except ValueError:
              print "Warning: Georgian translation not found in line", i   
         else:
              mydict[k] = v

If line.split() doesn't find two values, the unpacking does not take place and a ValueError is raised. We catch the exception and print a simple warning. If no exception is found (the else clause), then the entry is added to the python dictionary.

Note that this won't preserve line ordering in original file.

answered Jun 12 '14 at 08:32

Jaime Rodríguez-Guerra

345
2
9

Got it.Seems I can't use "raise" to do so. i just wanted it to print out like actual error all in red and stuff. Thanks anyways. Sorry for my English – temo Jun 12 '14 at 10:27
You might want to check this [question](http://stackoverflow.com/questions/287871/print-in-terminal-with-colors-using-python) to print colors in terminal. – Jaime Rodríguez-Guerra Jun 13 '14 at 10:29
1

Got it.Thanks man. Finally i talked with teach. and he said it's ok code to stop working after this error ) So it's done with simple raise ValueError("Thing"). I've learnt many new stuff from the comments , Thanks guys – temo Jun 14 '14 at 11:39

Python Raise Error (to display in shell) , then do rest of the code

3 Answers3