Phone-Number RegEx

Question

I need a regex that converts +442070320811 to 2070 320811.

Using this regex \(\d{4})(\d{6})(\d*)$ gives me 4420 703208

Can anyone advise how I can start the match after the 44?

possible duplicate of [A comprehensive regex for phone number validation](http://stackoverflow.com/questions/123559/a-comprehensive-regex-for-phone-number-validation) — hsz, Jun 13 '14 at 14:02

score 0 · Answer 1 · answered Jun 13 '14 at 14:03

0

This should work:

\+\d{2}(\d{4})(\d{6})(\d*)$

answered Jun 13 '14 at 14:03

Julian Irwin

score 0 · Accepted Answer · answered Jun 13 '14 at 14:09

0

Search: \+44(\d{4})(\d{6}\b)

Replace: $1 $2 or \1 \2 depending on language / environment.

answered Jun 13 '14 at 14:09

zx81

Thanks, I should have mentioned this is javascript. – user3737941 Jun 13 '14 at 14:59
Glad it worked, hope to see you again. Hey btw, I notice you haven't yet voted on Stack. If this answer helps and for any answer you find helpful, please consider voting up as this is how the rep system works.:) No obligation of course! Thanks for listening to my 10-second SO rep tut. – zx81 Jun 13 '14 at 15:02

Braj · Answer 3 · 2014-06-13T14:47:07.107

0

JavaScript:

text.replace(/(\+44)(\d{4})/g,'$2 ');

Java:

text.replaceAll("(\\+44)(\\d{4})","$2 ")

Simply use regex grouping feature that groups pattern inside parenthesis ().

Online demo on regex101 and debuggex

edited Jun 13 '14 at 14:47

answered Jun 13 '14 at 14:28

Braj

This worked perfectly for uk numbers but it turns out there are other country codes too so gradi3nt's solution addressed both fortunately. – user3737941 Jun 13 '14 at 14:58
You have not mentioned it in your post. If you did it then I will definitely provide you solution as per your need. – Braj Jun 13 '14 at 14:59
where have you mentioned that what language are you using. Is your question is complete in the context of you original issue? – Braj Jun 13 '14 at 15:00
You are agree with gradi3nt's solution but still you have accepted other one. Why? – Braj Jun 13 '14 at 15:02

score 0 · Answer 4 · edited Jun 13 '14 at 15:04

0

This also worked:

^.{2}((\d{4})(\d{6})(\d*)$)

Then I could refer to the sections using $2,$3 and $4

edited Jun 13 '14 at 15:04

Braj

answered Jun 13 '14 at 15:03

user3737941

OK so finally you got the answer. – Braj Jun 13 '14 at 15:04
Have you tested it on the links that I provided you? Is it working? – Braj Jun 13 '14 at 15:05
Yes, I did test it on those links and it is working fine so thanks for that. – user3737941 Jun 17 '14 at 12:09

4 Answers4