I have tried all the following:
import java.io.BufferedInputStream;
import java.io.File;
import java.io.FileInputStream;
import java.io.IOException;
import java.io.InputStream;
import java.net.URLConnection;
import java.nio.file.Files;
public class mimeDicom {
    public static void main(String[] argvs) throws IOException{
        String path = "Image003.dcm";
        String[] mime = new String[3];
        File file = new File(path);
        mime[0] = Files.probeContentType(file.toPath());
        mime[1] = URLConnection.guessContentTypeFromName(file.getName());
        InputStream is = new BufferedInputStream(new FileInputStream(file));
        mime[2] = URLConnection.guessContentTypeFromStream(is);
        for(String m: mime)
            System.out.println("mime: " + m);
    }
}
But the results are still: mime: null for each of the tried methods above and I really want to know if the file is a DICOM as sometimes they don't have the extension or have a different one.
How can I know if the file is a DICOM from the path?
Note: this is not a duplicate of How to accurately determine mime data from a file? because the excellent list of magic numbers doesn't cover DICOM files and the apache tika gives application/octet-stream as return which doesn't really identify it as an image and it's not useful as the NIfTI files (among others) get the exactly same MIME from Tika.