How to validate url in java?

Question

I have one inputtext Where I have to enter a link .
How I am going to validate that string is a url(link) or not. Example-

Pattern p = Pattern
                .compile("(@)?(href=')?(HREF=')?(HREF=\")?(href=\")?(http://)?[a-zA-Z_0-9\\-]+(\\.\\w[a-zA-Z_0-9\\-]+)+(/[#&\\n\\-=?\\+\\%/\\.\\w]+)?");

        Matcher m = p.matcher("https://mail.google.com");
        System.out.println(m.matches());

This code gives also false.I am not getting what was the problem in that code.
Or please refer another logic to validate the url.
I had already used UrlValidator urlValidator = new UrlValidator();
But I dont want to use this .jar

This is the another method this method validate properly but I that url is not available.How to check this requirement? example-

public static void main(String[] args) {
        String b = "http://11155555.com/";
        System.out.println(isUrl(b));

    }

    public static boolean isUrl(String str) {
        Pattern urlPattern = Pattern.compile(
                "((https?|ftp|gopher|telnet|file):((//)|(\\\\\\\\))+[\\\\w\\\\d:#@%/;$()~_?\\\\+-=\\\\\\\\\\\\.&]*)",
                Pattern.CASE_INSENSITIVE);
        Matcher matcher = urlPattern.matcher(str);
        if (matcher.find()) {
            return true;
        } else {
            return false;
        }
    }

Thanks in advanced.

Java is to Javascript as ham is to hamster. Please pay attention to your tags. — Boris the Spider, Jun 24 '14 at 10:16
`URL` has a [`String` constructor](http://docs.oracle.com/javase/7/docs/api/java/net/URL.html#URL(java.lang.String)) that throws a `MalformedURLException`... — Boris the Spider, Jun 24 '14 at 10:17

score -1 · Answer 1 · answered Jun 24 '14 at 10:14

-1

Try this one :

 public static boolean isUrl(String str){
    Pattern urlPattern = Pattern.compile("((https?|ftp|gopher|telnet|file):((//)|(\\\\\\\\))+[\\\\w\\\\d:#@%/;$()~_?\\\\+-=\\\\\\\\\\\\.&]*)",Pattern.CASE_INSENSITIVE);
         Matcher matcher = urlPattern.matcher(str);
    if (matcher.find()) 
             return true;
        else
            return false;
}

answered Jun 24 '14 at 10:14

Keval Trivedi

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This function gives required output but this is correct method to check? – vijayk Jun 24 '14 at 10:21
@vijayk Yes what is the problem with that ? – Keval Trivedi Jun 24 '14 at 10:23
I just confirm . I dont have problem. – vijayk Jun 24 '14 at 10:24
also find the another solution : http://stackoverflow.com/questions/15009573/url-validation-in-java – Keval Trivedi Jun 24 '14 at 10:30
Suppose this is the example http://11155555.com which is return true but this is not a valid url. Then how can you check it? – vijayk Jun 24 '14 at 10:33
@vijayk your link is not available. – Keval Trivedi Jun 24 '14 at 10:50
please find http://1111.com is available on internet. so it may possible this type of sites are available. – Keval Trivedi Jun 24 '14 at 11:00
this method check's only URL is valid. it not checks weather it is available or not on internet. – Keval Trivedi Jun 24 '14 at 11:10
@keval-- If want to check the urls like www.google.com then what I want change the code? I dont want to check http:// character.. – vijayk Jun 27 '14 at 10:41

How to validate url in java?

1 Answers1