match the order of an array to another array

Question

Is there anyway to match two arrays to see if they are identical, including the order they are in. so [1,2,3,4] would match to [1,2,3,4] but not [1,3,2,4], [2,1,4,3] etc

Answer 1

Just try with:

var a = [1,2,3,4],
    b = [1,3,2,4],
    equals = a.length == b.length;

if (equals) {
  for (var i = 0; i < a.length; i++){
    if (a[i] !== b[i]) {
      equals = false;
      break;
    }
  }
}

Answer 2

var a  = [1,2,3,4];
var b = [1,3,2,4];
var c = [1,2,4,3];
var d = [1,2,3,4];

if(a.join('|') === b.join('|')) {
    console.log('Same');    
}
else {
    console.log('Not same');    
}

Answer 3

try this logic, i hope it will help you

 var arr1 = [1,2,3,4];
 var arr2 = [1,2,4,4];
 var verify = true;

 for( var x = 0; x < arr1.length; x++ ){
    if( !(arr1[x] == arr2[x]) ){
       verify = false;
       break;
    }
 }

 if(verify){
   alert("match");
 }
 else{
    alert("not match");
 }