passing 2d array to function with in c

Question

Is there any way to pass 2D array to a function as function(arr,m,n) and the function defenition as void function(int **p,int m,int n) ie, Without explicitly specifying array size ??

possible duplicate of [passing 2D array to function](http://stackoverflow.com/questions/8767166/passing-2d-array-to-function) — πάντα ῥεῖ, Jul 19 '14 at 09:36
Related: http://stackoverflow.com/questions/232691/how-can-i-get-the-size-of-an-array-from-a-pointer-in-c — alk, Jul 19 '14 at 11:20
No. There is no way to pass the 2D array to a function Without explicitly specifying array size. for both 1D and 2d array you need to pass the array size to a function — Sathish, Jul 19 '14 at 12:15

score 1 · Accepted Answer · answered Jul 19 '14 at 10:32

Let us C has a good explanation about how to pass two D array as parameter.

I usually use these two ways for passing 2D array as parameter. But you need to specify the size explicitly.

void display1(int q[][4],int row,int col){
    int i,j;
    for(i=0;i<row;i++)
    {
        for(j=0;j<col;j++)
            printf("%d",q[i][j]);
        printf("\n");
    }
}

void display2(int (*q)[4],int row,int col){
    int i,j;
    int *p;
    for(i=0;i<row;i++)
    {
        p=q+i;
        for(j=0;j<col;j++)
            printf("%d",*(p+j));
        printf("\n");
    }
}
int main()
{
   int a[3][4]={1,2,3,4,5,6,7,8,9,0,1,6};
   display1(a,3,4);
   display2(a,3,4);
}

It's probably worth noting that in C99, this also works with variable-length arrays. — The Paramagnetic Croissant, Jul 19 '14 at 10:49

passing 2d array to function with in c

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