Assign data member of a domain class using Spring

Question

Is it possible?

Here is a more detailed case:

class A {
    private service x;

    //other members
    //some more methods.
}

bean definition is available for service but I do not want class A to be a spring bean and neither x to be static.

Is this achievable.

EDIT:

My spring configuration:

<bean id="Service" class="com.xx.yy.Service" />
<--!I do not register class A as a bean. Hence cannot use @autowired directly.-->

@DarshanLila yes. but not the whole class. I have a bean for the service but I just want to initialize the data member in this class. — Aman Deep Gautam, Aug 04 '14 at 08:52
If you don't tell spring that your class A is a bean (using annotation or XML), spring won't manage them. — Athanor, Aug 04 '14 at 08:54
@Athanor I am not asking spring to manage them. I just need a way to assign a data member which is managed by spring. — Aman Deep Gautam, Aug 04 '14 at 09:40
@DarshanLila Hope you are talking about this:http://stackoverflow.com/questions/7414794/difference-between-contextannotation-config-vs-contextcomponent-scan. This needs the bean to be regiested with @Compoment, if I am not wrong. I do not want to register `class A` as a bean. — Aman Deep Gautam, Aug 04 '14 at 12:19
@Athanor I have edited the question with more details. Here is a very similar question but the members are that need to be assigned are static:http://stackoverflow.com/questions/11324372/how-to-make-spring-inject-value-into-a-static-field — Aman Deep Gautam, Aug 04 '14 at 12:26

slavik · Answer 1 · 2014-08-04T12:42:44.530

0

I think you should create the factory for instances of class A which should take care of setting x.

@Service
class FactoryA {

  @Autowired service x;

  public A create() {
    return new A(x);
  }

}

edited Aug 04 '14 at 12:42

answered Aug 04 '14 at 12:34

slavik

But does it even qualify for factory pattern? I do not a decision to be made at run time. – Aman Deep Gautam Aug 05 '14 at 11:40
Of course it does. Take a look on Building blocks of DDD :) – slavik Aug 05 '14 at 11:43

score 0 · Accepted Answer · answered Aug 04 '14 at 12:48

0

It can only be achieved by manually getting the bean from the context.

Service service = context.getBean(Service.class);
A a = new A(service);

answered Aug 04 '14 at 12:48

Bart

is something close to this: http://stackoverflow.com/questions/11324372/how-to-make-spring-inject-value-into-a-static-field not possible. – Aman Deep Gautam Aug 04 '14 at 15:14

2 Answers2