How to separate argv[] input to two different strings on C?

Question

I am new in programming and currently learning on C. Could you please assist me on solving below's case?

An example of this will be if a user is entering "cbamike", I would like to separate it into two strings: cba and mike.

I tried below's code but it doesnt work:

#include <stdio.h>;

int main (int argc, string argv[])
{
    char* input[50] = argv[1];
    char* first[10];
    char* second[10];
    sprintf(first, "%c %c %c", input[0], input[1], input[2]);
    sprintf(second, "%c %c %c %c", input[3], input[4], input[5], inpput[6]);
    printf("%s\n", input);
    printf("%s\n", first);
    printf("%s\n", second);
}

`string` data type is not available in `C`. this is not valid `C` code. — Jayesh Bhoi, Sep 08 '14 at 06:06
You need to allocate space for `first` and `second` before you can write into them. — Barmar, Sep 08 '14 at 06:08
What are the criteria for splitting other strings, such as "abcdef", "nineelephantsawaltzing", etc? — Jonathan Leffler, Sep 08 '14 at 06:15

score 2 · Accepted Answer · edited May 23 '17 at 12:21

2

There is no string in c, you can use strncpy to get first few characters as aswered there: Strings in c, how to get subString

int main (int argc, string argv[])
{
    char* input = argv[1];
    char first[4];
    char second[5];

    strncpy(first, input, 3);
    strncpy(second, input + 3, 4);

    first[3] = second[4] = '\0';
}

edited May 23 '17 at 12:21

Community

1
1

answered Sep 08 '14 at 06:09

Mohammad Jafar Mashhadi

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score 1 · Answer 2 · answered Sep 08 '14 at 06:16

#include <stdio.h>
#include <string.h>

int main (int argc, char* argv[])
{
    if(argc >= 2)
    {
        const int len = strlen(argv[1]) / 2;
        char str1[len + 2], str2[len + 2];
        snprintf(str1, len + 1, "%s", argv[1]);
        snprintf(str2, len + 2, "%s", argv[1] + len);
        printf("1: %s\n2: %s\n", str1, str2);
    }
    return 0; 
}

How to separate argv[] input to two different strings on C?

2 Answers2