Equivalent to Debug.Assert() for when the DEBUG symbol is not defined?

Question

I am looking for syntax that will test an expression and throw an exception if the result is false AND the DEBUG symbol is missing. But not when it is there.

I know I can use:

#if !DEBUG
  Trace.Assert(condition);
#endif

And I know I can use:

#if !DEBUG
  SomeGlobal.Production = true;
#endif

So I can write:

Trace.Assert(SomeGlobal.Production && condition);

to avoid having the compilation instructions in different places.

Any other way?

@YuliamChandra Read the question again, that’s the opposite of what OP wants. — Konrad Rudolph, Sep 09 '14 at 14:17
What is the issue with the approach which you are using ie, `trace.assert(SomeGlobal.Production && condition);` — Rahul Tripathi, Sep 09 '14 at 14:19
I tried to improve your title. You can change it back if it does not reflect what you meant. — dee-see, Sep 09 '14 at 14:20
Are you asking how you can detect `DEBUG` without using `#if`? — DLeh, Sep 09 '14 at 14:20
to the editor of the original post. when someone comes here saying "why the *** would you like to do that?" i'm blaming you:) — user1852503, Sep 09 '14 at 14:20
Why not, `static void CustomAssert(bool condition){ if(!condition) throw new Exception(); }`? — kevin, Sep 09 '14 at 14:22
possible duplicate of [Segregating Debug and Release Code in C#](http://stackoverflow.com/questions/3311390/segregating-debug-and-release-code-in-c-sharp) — Margus, Sep 09 '14 at 14:36
Take a look at http://stackoverflow.com/questions/8230191/c-sharp-conditional-attribute for workarounds. — filhit, Sep 09 '14 at 14:38

score 5 · Accepted Answer · answered Sep 09 '14 at 14:22

[Conditional("RELEASE")]
public static void AssertRelease(bool condition)
{
    Trace.Assert(condition);
}

And make sure to define "RELEASE" in Release configuration,

ConditionalAttribute is a good way to do this.

Indicates to compilers that a method call or attribute should be ignored unless a specified conditional compilation symbol is defined.

Just like Debug.Assert, calls to this method are left out by the compiler if the condition is not met.

score 3 · Answer 2 · answered Sep 09 '14 at 14:27

Try this out:

#if !DEBUG
#define NOTDEBUG
#endif

namespace Test123
{
    using System;
    using System.Diagnostics;

    class Program
    {
        static void Main(string[] args)
        {
            var someCondition = false;

            Trace(someCondition);
        }

        [Conditional("NOTDEBUG")]
        static void Trace(bool condition)
        {
            if (!condition)
            {
                throw new Exception();
            }
        }
    }
}

See:

http://msdn.microsoft.com/en-gb/library/aa288458(v=vs.71).aspx

Equivalent to Debug.Assert() for when the DEBUG symbol is not defined?

2 Answers2