Recurring decimal rounding to second place

Asked Sep 10 '14 at 15:19

Active Sep 10 '14 at 15:52

Viewed 34 times

I have a division 4/3 which produces 1.33333333... I am storing the result in java double and I want to round this result to 1.34. How can this be done in Java ?

import java.text.*;
import java.math.RoundingMode;
public class HelloWorld{

     public static void main(String []args){


     DecimalFormat decimalFormat = new DecimalFormat("#.##");
     decimalFormat.setRoundingMode(RoundingMode.HALF_UP);
      String dd =decimalFormat.format(1.33333333);
      System.out.println(dd);
     }
}

Works with (Math.ceil(1.333333 * 100) / 100.0) but not with DecimalFormat

edited Sep 10 '14 at 15:52

asked Sep 10 '14 at 15:19

AdityaKapreShrewsburyBoston

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http://stackoverflow.com/questions/153724/how-to-round-a-number-to-n-decimal-places-in-java – Am_I_Helpful Sep 10 '14 at 15:23
Thanks but that does not work, I tried with all the rounding modes – AdityaKapreShrewsburyBoston Sep 10 '14 at 15:37
1

Why would you want `1.34` and `1.33` is closer to the correct answer? – Peter Lawrey Sep 10 '14 at 15:40
I want to convert it (1.33 or 1.34) to hours and minutes and it makes difference there of 1 minute – AdityaKapreShrewsburyBoston Sep 10 '14 at 15:40
2

You can do `Math.ceil(x * 100) / 100.0` and this will turn 1.33333 into 1.34 – Peter Lawrey Sep 10 '14 at 15:41
If two decimal places is not enough, I suggest using more decimal places. – Peter Lawrey Sep 10 '14 at 15:42
around how many for conversion to hr,mins & seconds? – AdityaKapreShrewsburyBoston Sep 10 '14 at 15:44

Recurring decimal rounding to second place

0 Answers0