if statement not functioning properly

Question

Hi stackers,

      System.out.print("Enter your first name:  ");
  firstName = keyboard.nextLine();
  if(firstName!="Mike"&&firstName!="mike"&&firstName!="Diane"&&firstName!="diane")
  {
      System.out.println("derp");
  }
  else
      discount=true;

however, this is the result:

Enter your first name:  diane
derp

if anyone can tell me what I'm doing wrong that would be great thank you very much!

I tried messing with the conditions of the statement to no avail — Metalmine, Sep 17 '14 at 05:21
Also, for your specific case - `!firstName.equalsIgnoreCase("mike") && !firstName.equalsIgnoreCase("diane")` — Elliott Frisch, Sep 17 '14 at 05:23
You need to use the `.equals()` method. == and != check the instance, not the content of the String. — , Sep 17 '14 at 05:23
Use the String.equals(String other) function to compare strings, not the == operator. — Owen Cao, Sep 17 '14 at 05:23

score 0 · Answer 1 · answered Sep 17 '14 at 05:24

public class Test{

    public static void main(String[] args) {

        System.out.print("Enter your first name:  ");
        Scanner keyboard = new Scanner(System.in);
        String firstName = keyboard.nextLine();
        if (!(firstName.equalsIgnoreCase("mike") || (firstName.equalsIgnoreCase("diane")))) {
            System.out.println("derp");
        } else
            System.out.println("true");
    }
}

Output

Enter your first name:  diane
true

if statement not functioning properly

1 Answers1