Getting a sorted uniq list of loggedin users with pipes

Question

I am trying to figure out how to get a list of logged in users and then with pipes sorting this list and only show every unique occurence.

I am almost there but the problem is that the "who-command" doesnt seem to allow to list just the user by name - it lists others parameters such as logintime, threads and so on. That results in making every every line unique.

here is my command

who | sort | uniq

and the result:

eric     :3           2014-09-25 15:23 (:3)
karen    :0           2014-09-25 14:41 (:0)
karen    pts/0        2014-09-25 14:48 (:0)
john     :2           2014-09-25 15:23 (:2)
carol    :1           2014-09-25 15:22 (:1)
carol    pts/25       2014-09-25 15:22 (:1)
admin    :4           2014-09-25 15:23 (:4)

So - how do I get a list of only the unique names in a list?

score 1 · Accepted Answer · answered Sep 25 '14 at 14:07

1

Take the first column only:

who | cut -d ' ' -f 1 | sort -u

answered Sep 25 '14 at 14:07

John Zwinck

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score 1 · Answer 2 · edited May 23 '17 at 12:05

1

I'd use:

who | awk '{print $1}' | sort | uniq

But there is more than one solution:

edited May 23 '17 at 12:05

Community

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answered Sep 25 '14 at 14:08

Benjamin

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Getting a sorted uniq list of loggedin users with pipes

2 Answers2