I'm fairly new to Rust so I came across this piece of code in the official Guide
let input = io::stdin().read_line()
.ok()
.expect("Failed to read line");
let input_num: Option<uint> = from_str(input.as_slice());
let num = match input_num {
Some(num) => num,
None => {
println!("Please input a number!");
return;
}
};
While the understand the first two statements (on input and inputnum), I'm not quite sure about the match statement. So I checked the documentation which shows that Option<T> can take two values , either None or Some(T) for some (object?) T. So I tested the following code:
io::println(
match input_num {
Some(num) => "somenum",
None => {
println!("Please input a number only!");
return;
}
}
);
This code works as expected; it prints somenum if you enter a number and otherwise it prints the error message. However, the compiler gives a warning stating: warning: unused variable:num, #[warn(unused_variable)] on by default. This confirmed my suspicions that the num inside the `match is used as a variable.
Question: How is it possible that rust does not complain about (in the Guide's example) having two variables with the same name num? Or does it "hand over" the pointer to the inside num to the outside num?
Also in the case of an empty return what exactly is returned? I'm guessing it is unit () because it is mentioned here that
functions without a
-> ...implicitly have return type()
Edit: Sorry for missing the obvious point. The return directly exits the function without bothering to put anything into num.
P.S. I noticed that using cargo build to compile does not give warnings the second time around (not making any changes). Does cargo keep tracking of versions or something?