How to check iphone model using swift

Question

How we can check model of iPhone (e.g iPhone 4/ iPhone5) in Swift. Using following code I can check whether it is iPhone of iPod.

let iphoneModel = UIDevice.currentDevice().model
if (iphoneModel == "iPhone"){
        println("Iphone 4")
    }

I need to know specifically which iPhone model it is.

Kindly check this: http://stackoverflow.com/questions/26028918/ios-how-to-determine-iphone-model-in-swift — Lie-An, Sep 30 '14 at 09:44
Give a look at this [link](http://stackoverflow.com/questions/26028918/ios-how-to-determine-iphone-model-in-swift) — nikhil84, Sep 30 '14 at 09:52

score 31 · Accepted Answer · edited May 23 '17 at 12:09

Use the following code. (Reference from)

enum UIUserInterfaceIdiom : Int
{
    case Unspecified
    case Phone
    case Pad
}

struct ScreenSize
{
    static let SCREEN_WIDTH         = UIScreen.mainScreen().bounds.size.width
    static let SCREEN_HEIGHT        = UIScreen.mainScreen().bounds.size.height
    static let SCREEN_MAX_LENGTH    = max(ScreenSize.SCREEN_WIDTH, ScreenSize.SCREEN_HEIGHT)
    static let SCREEN_MIN_LENGTH    = min(ScreenSize.SCREEN_WIDTH, ScreenSize.SCREEN_HEIGHT)
}

struct DeviceType
{
    static let IS_IPHONE_4_OR_LESS  = UIDevice.currentDevice().userInterfaceIdiom == .Phone && ScreenSize.SCREEN_MAX_LENGTH < 568.0
    static let IS_IPHONE_5          = UIDevice.currentDevice().userInterfaceIdiom == .Phone && ScreenSize.SCREEN_MAX_LENGTH == 568.0
    static let IS_IPHONE_6          = UIDevice.currentDevice().userInterfaceIdiom == .Phone && ScreenSize.SCREEN_MAX_LENGTH == 667.0
    static let IS_IPHONE_6P         = UIDevice.currentDevice().userInterfaceIdiom == .Phone && ScreenSize.SCREEN_MAX_LENGTH == 736.0
    static let IS_IPAD              = UIDevice.currentDevice().userInterfaceIdiom == .Pad && ScreenSize.SCREEN_MAX_LENGTH == 1024.0
}

and use it as:

if DeviceType.IS_IPHONE_6P {
            println("IS_IPHONE_6P")
}

I created a Swift Class just for this purpose: https://github.com/mikeKane/findThatModel — mKane, Aug 19 '16 at 20:08

score 5 · Answer 2 · answered Jun 22 '17 at 11:59

SWIFT 3

enum UIUserInterfaceIdiom : Int
{
    case Unspecified
    case Phone
    case Pad
}

struct ScreenSize
{
    static let SCREEN_WIDTH         = UIScreen.main.bounds.size.width
    static let SCREEN_HEIGHT        = UIScreen.main.bounds.size.height
    static let SCREEN_MAX_LENGTH    = max(ScreenSize.SCREEN_WIDTH, ScreenSize.SCREEN_HEIGHT)
    static let SCREEN_MIN_LENGTH    = min(ScreenSize.SCREEN_WIDTH, ScreenSize.SCREEN_HEIGHT)
}

struct DeviceType
{
    static let IS_IPHONE_4_OR_LESS  = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.SCREEN_MAX_LENGTH < 568.0
    static let IS_IPHONE_5          = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.SCREEN_MAX_LENGTH == 568.0
    static let IS_IPHONE_6          = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.SCREEN_MAX_LENGTH == 667.0
    static let IS_IPHONE_6P         = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.SCREEN_MAX_LENGTH == 736.0
    static let IS_IPAD              = UIDevice.current.userInterfaceIdiom == .pad && ScreenSize.SCREEN_MAX_LENGTH == 1024.0
}

and for the use

if DeviceType.IS_IPHONE_6P{
    print("IS_IPHONE_6P")
}

score 5 · Answer 3 · answered Jan 29 '19 at 07:52

Swift 4 + iPhone Xr, Xs, Xs Max support

import UIKit

enum UIUserInterfaceIdiom : Int {
    case Unspecified
    case phone
    case pad
}

struct ScreenSize {
    static let screenWidth = UIScreen.main.bounds.size.width
    static let screenHeight = UIScreen.main.bounds.size.height
    static let screenMaxLength = max(ScreenSize.screenWidth, ScreenSize.screenHeight)
    static let screenMinLength = min(ScreenSize.screenWidth, ScreenSize.screenHeight)
}

struct DeviceType {
    static let iPhone4OrLess  = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.screenMaxLength < 568.0
    static let iPhoneSE = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.screenMaxLength == 568.0
    static let iPhone8 = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.screenMaxLength == 667.0
    static let iPhone8Plus = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.screenMaxLength == 736.0
    static let iPhoneXr = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.screenMaxLength == 896.0
    static let iPhoneXs = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.screenMaxLength == 812.0
    static let iPhoneXsMax = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.screenMaxLength == 896.0
    static let iPad = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.screenMaxLength == 1024.0
}

And use :

 if DeviceType.iPhoneXsMax {
      print("is Max here")
 }

score 3 · Answer 4 · answered May 02 '18 at 11:59

Swift 4:

enum UIUserInterfaceIdiom : Int
{
  case Unspecified
  case Phone
  case Pad
}

struct ScreenSize
{
  static let SCREEN_WIDTH         = UIScreen.main.bounds.size.width
  static let SCREEN_HEIGHT        = UIScreen.main.bounds.size.height
  static let SCREEN_MAX_LENGTH    = max(ScreenSize.SCREEN_WIDTH, ScreenSize.SCREEN_HEIGHT)
  static let SCREEN_MIN_LENGTH    = min(ScreenSize.SCREEN_WIDTH, ScreenSize.SCREEN_HEIGHT)
}

struct DeviceType
{
  static let IS_IPHONE_4_OR_LESS  = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.SCREEN_MAX_LENGTH < 568.0
  static let IS_IPHONE_5          = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.SCREEN_MAX_LENGTH == 568.0
  static let IS_IPHONE_6          = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.SCREEN_MAX_LENGTH == 667.0
  static let IS_IPHONE_6P         = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.SCREEN_MAX_LENGTH == 736.0
  static let IS_IPAD              = UIDevice.current.userInterfaceIdiom == .pad && ScreenSize.SCREEN_MAX_LENGTH == 1024.0
}

Example case:

 if DeviceType.IS_IPHONE_5 {
      //TODO:
 }

How to check iphone model using swift

4 Answers4