How to get uploaded image file format without using guessExtension()?

Question

I have a laravel 4.1 project running on PHP 5.3.28 and I am trying to find a way to get the file extension from a certain image that fails whenever I use guessExtension() like so:

$format = Input::file('image')->guessExtension();

Every other image I've tried uploading has had no problem using guessExtension(), but it seems Symphony is unable to recognize the mimeType for this specific image:

object(Symfony\Component\HttpFoundation\File\UploadedFile)[9]
  private 'test' => boolean false
  private 'originalName' => string 'herewithme.png' (length=14)
  private 'mimeType' => string 'application/octet-stream' (length=24)
  private 'size' => int 0
  private 'error' => int 1

and my application fails with the following message:

The file "" does not exist

I was thinking about doing something like this:

   $filename = Input::file('image')->getClientOriginalName();

    if(strpos($filename, '.png') !== false)
    {
        $format = 'png';           
    }
    elseif(strpos($filename, '.jpg') !== false)
    {
        $format = 'jpg';            
    }

However, I'm afraid of the random case that a file might cause problems from being named something like pdf.png.jpg (or something to that effect), so I'm hesitant about getting the file format this way. Can anyone think of a better way to do this?

Maybe just invoke the Linux/Unix `file` command on the uploaded file? — wallyk, Oct 01 '14 at 21:17
to get an extension `$ext = pathinfo($filename, PATHINFO_EXTENSION);` but it doesn't solve your problem. I don't know internals of Laravel , but it is possible that maximum upload file size is reached , set in php.ini , may be cause this. Also in your var_dump there is `private 'error' => int 1` can you getErrorMessage or similar on that class object — BojanT, Oct 01 '14 at 21:34

score 0 · Accepted Answer · answered Oct 01 '14 at 21:20

0

You can do it with substr.

You can try $ext = substr($filename,-4);

answered Oct 01 '14 at 21:20

Aqib1604

292
1
7

1

I would rather use explode() and delimit by '.', for a more generic and fail safe solution. – tomazahlin Oct 02 '14 at 22:43
Yes We can.And I am agree its better than mine. It will work with all. – Aqib1604 Oct 02 '14 at 22:59

Jared Eitnier · Answer 2 · 2014-10-01T21:24:16.160

-1

Maybe try:

Input::file('image')->getClientMimeType();

or

Input::file('image')->getMimeType();

edited Oct 01 '14 at 21:24

answered Oct 01 '14 at 21:17

Jared Eitnier

7,012
12
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How to get uploaded image file format without using guessExtension()?

2 Answers2