Does c# short-circuit the &= and |= operator

Question

I know that the && operator and || operators are short-circuited in c#. But are the &= operators and |= operators as well? Suppose I have a statement:

bool a = doSomething();
a &= doNext();

Is this guaranteed to be equivalent to:

bool a = doSomething();
if(!a)
  a = doNext();

score 0 · Accepted Answer · answered Oct 07 '14 at 09:43

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I imagine that would actually be equivalent to:

a = a & doNext()

Google for bitwise operations to see more.

answered Oct 07 '14 at 09:43

Luke

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Yes, you're right. So it won't short-circuit. – arviman Oct 08 '14 at 05:31

score 0 · Answer 2 · answered Oct 07 '14 at 09:47

0

Yes it does http://msdn.microsoft.com/en-us/library/e669ax02.aspx and no it is not equal to &&. It is a short version of & operator plus assigment. doNext method would be called and executed for any "a" value.

answered Oct 07 '14 at 09:47

Zed

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So, by "Yes it does", you mean "No it does not short-circuit"? – Oct 07 '14 at 09:48
I missunderstood your question a little. I thought short-circuit means &= instead of = ... & ... . Sorry – Zed Oct 07 '14 at 09:53

Does c# short-circuit the &= and |= operator

2 Answers2