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I am trying to echo an image after fopen and fread it, but it shows as ascii code not as image format.

I found an answer:

Fopen function opens JPEG image as text

I implemented the header() line in my code but it seems that it try to open my current php file as jpg not the image.

Here is my code:

        $filename = $n.".jpg";
        //echo $n.'.jpg'; prints image_name.jpg
        $fp = fopen($filename, "r");
        $data = fread($fp, filesize($filename));

        header('Content-type: image/jpg'); //without the header line I can print the ascii
        echo $data; //I want to print my $data as image format not ascii

        fclose($fp);

(I don't know if it does matter but I am using latest version of XAMPP and W7)

Thanks in advance

Community
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yb_esc
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2 Answers2

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If you use fopen, try

$fp = fopen($filename, "rb");

to enforce binary mode. I'm lazy and use this:

$filename = $n.".jpg";
header('Content-type: image/jpg'); //without the header line I can print the ascii
echo file_get_contents($filename);
Ken Cheung
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I miss the point why you want to output the image through a script instead of serving it directly, since it is already a jpg image.

Nonetheless maybe you should try instead of echoing the file contents, using fpassthrough that outputs all remaining data on a file pointer

$filename = $n.".jpg";
$fp = fopen($filename, "r");

header('Content-type: image/jpg'); //without the header line I can print the ascii

fpassthru($fp)
fclose($fp);

You may also call readfile function directly http://php.net/manual/en/function.readfile.php without having to use fopen

montexristos
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