Compare Strings in Java

Question

why the first code gives output as "true" and second code gives output as "false"?

code 1 ............... String str1="abc"; String str2="abc";

  if (str1==str2)
      System.out.println("true");
  else
       System.out.println("false");

code 2

NOTE : Input to both string will be same value ....................

 Scanner sc=new Scanner(System.in);
 System.out.println("enter string 1");
 String String1=sc.next();
 System.out.println("enter string 2");
 String String2=sc.next();

 if(String1==String2)
     System.out.println("true");
 else
     System.out.println("false");

This is the *5,423,232th* time this has been asked – TheLostMind Oct 22 '14 at 04:48 — TheLostMind, Oct 22 '14 at 04:48
Stack Overflow should implement a search... – mkobit Oct 22 '14 at 04:50 — mkobit, Oct 22 '14 at 04:50

score 0 · Answer 1 · answered Oct 22 '14 at 04:48

0

The operator == checks the object identity The .equals() method checks if the value is equal to another string's value use:

if (str1.equals(str2)) {
    ...
}

answered Oct 22 '14 at 04:48

Victor2748

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does my first code equals to ' .equals() ' ? – Erandi Oct 22 '14 at 04:57

Compare Strings in Java

1 Answers1