Printing 2 dimensional char array in c++

Question

I dont understand why I can't print out this character array using the void function print_board which takes in the character array as parameter, initilize it and print it. Gives me [Error] invalid conversion from 'char' to 'char ()[8]' [-fpermissive] [Error] initializing argument 1 of 'void print_board(char ()[8])' [-fpermissive]

what am i missing or doing wrong here?

 #include <iostream>
 using namespace std;
 void print_board(char [8][8]);


 int main() {
 char board[8][8];
 print_board(board[8][8]);

return 0;
}


void print_board(char board[8][8])
{

for(int i = 0;i<8;i++)
    for(int j = 0; j<8; j++)
    {

    board[i][j] = '.';
    cout<<board[i][j];
    }



   }

score 0 · Answer 1 · answered Oct 25 '14 at 15:45

0

You're passing board[8][8] which is of type char.

print_board expects an array of char[8] given your definition of the function.

Change the invocation to print_board(board);

answered Oct 25 '14 at 15:45

igon

3,016
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its array supposed to store characters. – Oct 25 '14 at 15:46

score 0 · Accepted Answer · edited May 23 '17 at 12:00

0

In the main function you are not passing the array properly plus function header should be like this

print_board(board); // This should be in main

void print_board(board[][8])
{
    // Do something
}

For more detail visit Passing a 2D array to a C++ function

edited May 23 '17 at 12:00

Community

1
1

answered Oct 25 '14 at 15:45

Shravan40

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its: print_board(board[8][8]) – Oct 25 '14 at 15:48
Do add `cout<<"\n";` when inner `for(;;)` loop ends to print it like board, if you want – Shravan40 Oct 25 '14 at 15:51

Printing 2 dimensional char array in c++

2 Answers2