Java/Android will not allow "this" as parameter in Intent declaration

Question

I am defining an Intent inside of a protected function inside a private class. I am brand new to Java/Android and do not know how I pass the parameter to Intent. I have been using "this" in other Activities but I am getting a complaint from AndroidStudio.

Intent setSession = new Intent(this, posterSessionSetup.class);

Cannot resolve constructor Intent(.....

 private class AsyncCaller extends AsyncTask<String, Void, String> {
        protected String doInBackground(String... urls) {
            //get the text input and validate it
            EditText userName = (EditText)findViewById(R.id.txtUserName);
            EditText password = (EditText)findViewById(R.id.passWord);

            return readJSONFeed("mywebservice", userName.getText().toString(), password.getText().toString());
        }
        protected void onPostExecute(String result){
            try {
                JSONObject jsonObject = new JSONObject(result);
                JSONObject r = new JSONObject(jsonObject.getString("r"));
                String status = r.getString("status");
                String msg = r.getString("msg");
                if (status == "complete"){
    --------->>>>>> Intent setSession = new Intent(this, posterSessionSetup.class);
                    startActivity(setSession);
                }
                else {
                    Toast.makeText(getBaseContext(), r.getString("status") + ":" + r.getString("msg"), Toast.LENGTH_SHORT).show();
                }
            } catch(Exception e){
                Log.d("Read Json File", e.getLocalizedMessage());
            }

        }

    }

Not that it is related to your problem but `if (status == "complete"){` doesn't look good. Read http://stackoverflow.com/questions/513832/how-do-i-compare-strings-in-java — Pshemo, Nov 11 '14 at 20:47
That is my javaScript/PHP background showing. I will read up on contentEquals. Thank you~! — silversunhunter, Nov 11 '14 at 20:53
@Pshemo @ CQM.. You were right. It did not compare properly until I changed it to ContentEquals. — silversunhunter, Nov 11 '14 at 21:24

Patrick · Accepted Answer · 2014-11-11T20:56:31.120

3

You are in the inner class AsyncCaller so this refers to that class. You can use e.g. YourActivityClass.this if the outer class is named YourActivityClass to reference the outer class

edited Nov 11 '14 at 20:56

answered Nov 11 '14 at 20:50

Patrick

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so the main class is Public Login extends android.app.Activity{}.. I would use Login.class or Login.this? – silversunhunter Nov 11 '14 at 20:53
Login.this if your class is public class Login – Patrick Nov 11 '14 at 20:54

score 1 · Answer 2 · answered Nov 11 '14 at 20:47

1

This refers there to the asynctask inatance.

Uae the activity or whatever that class is embeded in.

answered Nov 11 '14 at 20:47

eduyayo

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Which, for example, can be accessed via `MainActivity.this`. Although that's not exactly pretty. – Ingo Bürk Nov 11 '14 at 20:48

Java/Android will not allow "this" as parameter in Intent declaration

2 Answers2