Java integer division result as double?

Question

I currently have this code:

    int kills = 1;
    int deaths = 2;

    double kdr = 0;

    if(kills > 0 && deaths == 0) {
        kdr = kills;
    } else if(kills > 0 && deaths > 0){
        kdr = kills/deaths;
    }

    System.out.println(kdr);

You can test it here.

Why is the output 0.00 and not 0.5?

This is a duplicate of many things. Just because you're assigning the result of an operation to a `double` doesn't make the operation itself get performed using `double` arithmetic... — Jon Skeet, Nov 12 '14 at 07:26

score 3 · Accepted Answer · answered Nov 12 '14 at 07:26

3

If kills/deaths < 1, you get 0, since the output of integer division is integer. This 0 is then cast to 0.0 to fit the double variable in which you store it.

In order to get a non-integer result, you have to cast one of the numbers to double :

 kdr = (double)kills/deaths;

answered Nov 12 '14 at 07:26

Eran

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Thank you. I should've tried that, i just assumed that dividing under a double would not need a cast. – ThatGuy343 Nov 12 '14 at 07:28
1

@ThatGuy343 Your division is performed on two integers, and therefore results in integer, and only the result is cast to double, to fit your kdr variable. – Eran Nov 12 '14 at 07:31

score 1 · Answer 2 · answered Nov 12 '14 at 07:27

1

Because your input values are integer. if you cast one oy them to a double youget the expected result:

 kdr = (double)kills/deaths;

answered Nov 12 '14 at 07:27

Jens

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Java integer division result as double?

2 Answers2